0.25x^2-5x+80=0

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Solution for 0.25x^2-5x+80=0 equation:


Simplifying
0.25x2 + -5x + 80 = 0

Reorder the terms:
80 + -5x + 0.25x2 = 0

Solving
80 + -5x + 0.25x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
0.25 the coefficient of the squared term: 

Divide each side by '0.25'.
320 + -20x + x2 = 0

Move the constant term to the right:

Add '-320' to each side of the equation.
320 + -20x + -320 + x2 = 0 + -320

Reorder the terms:
320 + -320 + -20x + x2 = 0 + -320

Combine like terms: 320 + -320 = 0
0 + -20x + x2 = 0 + -320
-20x + x2 = 0 + -320

Combine like terms: 0 + -320 = -320
-20x + x2 = -320

The x term is -20x.  Take half its coefficient (-10).
Square it (100) and add it to both sides.

Add '100' to each side of the equation.
-20x + 100 + x2 = -320 + 100

Reorder the terms:
100 + -20x + x2 = -320 + 100

Combine like terms: -320 + 100 = -220
100 + -20x + x2 = -220

Factor a perfect square on the left side:
(x + -10)(x + -10) = -220

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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